Question

JEE ADVANCE PRACTICE SERIES (CHE)
40 g $Ba{(MnO_4)}_2$ (Molar mass = 375) sample containing some inert impurities in acidic medium completely reacts with 125 mL of "33.6 V" of $H_2O_2$ .Find the percentage impurity of the sample.
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Answer 1

Explanation:

Mass of H2O2 8n 125ml solution = 17/5600×33.6×125g

So, Number of equivalants of H2O2=33.6×125/5600

As number of equivlants of both are same

x/375/10 = 33.6× 125/5600

So percentage is 70.31%