Question

JEE ADVANCED CHEMISTRY QUESTION SEPTEMBER 2020

Answer 1

Thank you for this information
Please mark me as brainlist

Answer 2

In thermodynamics, the P - V work done is given by, $W=-\int{dV}P_{ext}$

for a system undergoing a particular process, the work done is $W=-\int{dV}\left(\frac{RT}{V-b}-\frac{a}{V^2}\right)$

This equation is applicable to a

(A) system that satisfies the Van Der Waals equation of state.

(B) process that is reversible and isothermal

(C) process that is reversible and adiabatic

(D) process that is irreversible and at constant pressure.

solution : from Van far equation,

(P + an²/V²)(V - nb) = nRT

for one mole of gas,

(P + a/V²)(V - b) = RT

⇒PV - Pb + a/V - ab/V² = RT

⇒P(V - b) = RT - a(V - b)/V²

⇒ P = RT/(V - b) - a/V²

so it is clear that, the equation is applicable to the system that satisfies Van Der Waals equation of state.

if $P_{ext}=P$ means process is reversible. for Van Der Waals gas, expression is correct for all reversible process.

so the option (B) and (C) are also correct.

Therefore correct options are (A), (B) and (C).