JEE ADVANCED CHEMISTRY QUESTION SEPTEMBER 2020
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The structure of peptide is given below ,
if the absolute values of net charge of the peptide at pH = 2, pH = 6 and pH = 1w are |z₁| , |z₂| and |z₃| , respectively, then what is |z₁| + |z₂| + |z₃| ?
solution : at pH = 2 , NH₂ (1) and NH₂ (2) of Tyrosine and Lysine is positively charged and each of them has + 1 charge. so total charge , |z₁| = 2
at pH = 6, NH₂ of Lysine (+1) , COOH of glutamic acid (-1), so total charge |z₂| = |+1 - 1| = 0
at pH = 11, COOH of glutamic acid (-1) , COOH of Lysine (-1) and OH of phenol (-1) so total charge, |z₃| = |-1 -1 -1| = 3
Therefore the value of |z₁| + |z₂| + |z₃| = 2 + 0 + 3 = 5
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