JEE Advanced Exam
PHYSICS
CHEMISTRY
MATHEMATICS i
Exam End Time: 10:00 AM
Duration: 3:00:00 Time Left : 2:34:20
Y, X forms fcc packing and Y occupies
all the octahedral voids. If all the particles
along one body diagonal are removed
then the formula of the crystal would be
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When all the particles along one body diagonal are removed , 2X atoms from 1 corner are removed , 1Y particle and 2Z particles removed.
Hence new arrangement is X particle = 1/8 * 6 + 1/2* 6 = 15/4
Y particle = 6
Z particle = 3
X5Y4Z8 ---formula
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