Physics, asked by StrongGirl, 4 months ago

JEE ADVANCED PHYSICS QUESTION SEPTEMBER 2020

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Answered by abhi178
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When water is filled carefully in a glass, one can fill it to a height h above the rim of the glass due to the surface tension of water. To calculate h just before water starts flowing, model the shape of the water above the rim as a disc of thickness h having semicircular edges, as shown schematically in the figure. When the pressure of water at the bottom of this disc exceeds what can be withstood

due to the surface tension, the water surface breaks near the rim and water starts flowing from there. If the density of water, its surface tension and the acceleration due to gravity are 10³kg m−3, 0.07 Nm−1 and 10 ms−2, respectively, the value of h (in mm) is _

solution : as a disc of thickness h having semicircular edge, as shown schematically in the figure.

so, radius of disc , r = h/2

now pressure at the bottom of disc = pressure due to surface tension.

⇒ρgh = T/r

⇒ρgh = T/(h/2)

⇒ρgh² = 2T

⇒h² = 2T/ρg

putting values T = 0.07 N/m, ρ = 10³ kg/m³ and g = 10 m/s²

so, h² = (2 × 0.07)/(10³ × 10) = 14 × 10^-6

h = 3.74 × 10^-3 m = 3.74 mm

Therefore the value of h in mm is 3.74

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