Question

JEE Aspirants...Where ya At?... Brainliest For The Best!​

Answer 1

Answer :

7

Solution :

Given,  

1/( sinπ/n )   =   1/(sin2π/n) +   1/( sin3π/n)

=> 1/( sinπ/n )   -   1/( sin3π/n) =   1/(sin2π/n)

=>  (sin3π/n  - sinπ/n)/(sinπ/n sin3π/n)  =  1/(sin2π/n)

=> (2 cos2π/n sinπ/n)/(sinπ/n sin3π/n) =  1/(sin2π/n)

=>  2 cos2π/n sin2π/n = sin3π/n

=>  sin4π/n = sin3π/n

=> 4π/n = π - 3π/n

=> 7π/n = π

=> n = 7

Answer 2

ye Dekh RY...

This one is for you