Question

JEE level question. wrong answers will be deleted. 100 points for brainliest. I know the answer but need 100% correct method. BEST OF LUCK.​

Answer 1

Answer:

(2) 4 is the answer

Step-by-step explanation:

The discriminant of the quadratic equation is given by,

Δ=b^2 -4ac

It is determined from the coefficients of ax^2 +bx +c.

The value of discriminant reveals what types of roots the equation has.

If discriminant is greater than 0 then we will get real roots.

For, ax^2+bx+2=0

The discriminant = b^2 - 4ac

=b^2 - 8a

Equating this to 0

.°. b^2 -8a =0

.°. 8a = b^2

.°. a =b^2/8

a & b are positive integers and b is less than 6.

The values can be taken for b are => 1,2,3,4,5

when,

b = 1,a =1/8

b =2, a=4/8 =1/2

b=3 ,a =9/8

b =4,a =16/8 =2

b=5,a = 25/8

The only value of b that gives an integer value of a is 4.

Meaning: There is only one equation that can be formed that satisfy this condition.

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Answer 2

Step-by-step explanation:

The correct answer is 4

★ ax^2+bx+2=0

➡The values can be taken for b are => 1,2,3,4,5

The values can be taken for b are => 1,2,3,4,5when,b = 1,a =1/8b =2, a=4/8 =1/2b=3 ,a =9/8b =4,a =16/8 =2b=5,a = 25/8

so, 4 is the correct answer