Question

Jee main aspirants...?
/ Neet aspirants
..... Solve


a body moves with constant speed 10 metre per second in x-axis and turn left then average acceleration if time is 2 second....​

Answer 1

Initial velocity = 10 i

Final velocity = 10 j

Change in velocity = 10 j - 10 i

So, the magnitude = √(10² + 10²)

= 10√2 m/s

Hence, acceleration = (10√2)/2

= 5√2 m/s²

Hope, it'll help you.....