Question

JEE MAIN
PHYSICS
CHEMISTRY
MATHEMATICS
Question 16
A ball is projected at some angle with ground such that it is at a particular height
two times at t = 4s and t = 6s. Find the maximum height of the projecticle during
the motion.
50 m
(1)
(2)
(3)
80 m
125 m
180 m
01)
02)
3)
04​

Answer 1

Answer:

Explanation:

50m

80m

125m

180m

Answer :

C

Solution :

T=t1+t24+6=10s

10=2usinθg=⇒usinθ=50m/s

H max=u2sin2θg=125m