Question

jee mains 2019 question..i need answer with reason

Answer 1

Ok. So in option (a), Huckel's rule for aromaticity is obeyed since we have 2pi electrons.

Option (b) is anti-aromatic since it's having 8pi electrons.

Option (c) is aromatic as it has 6pi electrons.

And (d) is not aromatic since one carbon atom is not sp² hybridized.

So your answer is (2).