Question

Jee Mains 2020 2nd Sept. Shift - 1

When radiation of wavelength λ is used to illuminate a metallic surface, the stopping potential is V. When the same surface is illuminated with radiation of wavelength 3λ the stopping potential is V/4. If the threshold wavelength for the metallic surface is nλ then value of n will be _______ .​

Answer 1

Answer:

Os find the value of p for which 5p÷5-²=5²=5

Answer 2

Answer:

n=9

Explanation:

∴ λ0 = 9λ So, n = 9.

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