Chemistry, asked by StrongGirl, 7 months ago

JEE Mains chemistry question is in the image

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Answered by EnchantedGirl
6

ANSWER :- -97.

\\

SOLUTION:-

</p><p> \rightarrow \: [Ti(H_{2} O)_{6}] {}^{ + 3}   \\  \\  \\  \implies \:  \: Ti {}^{ + 3}  = 3d {}^{1} 4s {}^{0}  \\  \\  \\  \implies \:  t_{2g} {}^{1 \: 0 \: 0}  \\  \\  \\

 \rightarrow \: CFSE = (-0.4nt_{2g} + 0.6n_{eg}\triangle o + n(p)) \\  \\  \\  \implies \: ( - 0.4 \times 1)20300 =  - 8120cm {}^{ - 1}  \\  \\  \\  \implies \:  \frac{ - 8120}{83.7} kjpmole \:  =  - 97. \\  \\

Hence ,the answer is \boxed{-97}

HOPE IT HELPS :)

Answered by Anonymous
30

QUESTION :

For [Ti(H2O) 6]³+ the absorption maximum due to d - d transition is found to be 20,300 cm^-1, therefore the Crystal Field stabilization energy in kj/Mole is →

[GIVEN : 1 kJ/mole = 33.7 cm-¹ ]

GIVEN :

  • The formula (main) given, that is to be applied = [Ti(H2O) 6]³+

  • d - d transition is found which is =

20,300 cm-¹

TO FIND :

  • The Crystal Field stabilization energy in Kj/ mole is = ?

STEP-BY-STEP EXPLAINATION :

➠ The formula given = [Ti(H2O) 6]³+

➠ Ti+³ = 3d¹4s^0 (substituting here) (solving)

➠ t2g^100 (Gained value after solving the above)

→ Now, we will have to find here the field crystal (energy) in kJ/mole is →

ㅤㅤㅤㅤㅤas per the given value :

⟹ 1kJ/mole = 33.7 cm-¹

Substituting the value as per the given formula :

⟹ (-0.4×1) 20,300 = 8,120 cm-¹ㅤ

⟹ -8,120/83.7 kJ/mole (when reduced)

ㅤㅤㅤㅤ

⟹ -8,120/83.7 kJ/mole = -97 kJ/mole

Therefore, The crystal field stabilization energy in kJ/mole is = - 97 kJ/mole

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