Question

JEE MAINS CHEMISTRY QUESTION SEPTEMBER 2020

Answer 1

ANSWER.

$\sf \to \: e {}^{0} _{cell} = 2$

EXPLANATION.

$\sf \to \: equation \: are \: \\ \\ \sf \to \: {m}^{2 + } _{(aq)} + zn_{(s)} \longrightarrow \: m_{(s)} + zn {}^{2 + } _{(aq)} \\ \\ \sf \to \:\Delta g {}^{0} = - 386 \: kj \: mol {}^{ - 1}$

$\sf \to \: as \: we \: know \: that \: \\ \\ \sf \to \: \Delta g \: = - nf e {}^{0} _{cell} \\ \\ \sf \to \: - 386000 = - 2 \times 96500 \times e {}^{0} _{cell} \\ \\ \sf \to \: e {}^{0} _{cell} \approx \: 2 \\ \\ \sf \to \: value \: of \: e {}^{0} _{cell} = 2$