Question

JEE MAINS CHEMISTRY QUESTION SEPTEMBER 2020

Answer 1

Answer:

OPTION 3

Explanation:

Answer 2

Answer:

• The correct ratio is 3 : 1

Explanation:

$\rule{300}{1.5}$

Firstly let's find the percentage abundance of both isotopes in general.

So, let us assume that Percentage abundance of Cl₃₅ is x and that of Cl₃₇ be (100 - x).

So, Now

$\longmapsto\sf 35.5=\dfrac{35\times x}{100}+\dfrac{37\times (100-x)}{100}\\\\\\\\\longmapsto\sf 35.5=\dfrac{35\;x}{100}+\dfrac{3700-37\;x}{100}\\\\\\\\\longmapsto\sf 35.5=\dfrac{35\;x+3700-37\;x}{100}\\\\\\\\\longmapsto\sf -2\;x+3700=35.5\times 100\\\\\\\\\longmapsto\sf -2\;x+3700=3550\\\\\\\\\longmapsto\sf 2\;x=3700-3550\\\\\\\\\longmapsto\sf 2x=150\\\\\\\\\longmapsto\sf x=\dfrac{150}{2}\\\\\\\\\longmapsto \boxed{\sf x=75\;\%}$

So, value of 100 - x will be 25 %.

Therefore, abundance of Cl₃₅ is 75 % and Cl₃₇ is 25 %. So, Clearly the ratio is of 3 parts : 1 part.

Hence, Option -(3) is correct i.e. the ratio is 3 : 1.

$\rule{300}{1.5}$