JEE MAINS MATHS QUESTION SEPTEMBER 2020
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In a group 63% people read news paper A while 76% people read news paper B.
To find : x% people read both A and B. then value of x may be..
solution : let n(u) is total no of people
n(A) is no of people reading news paper A
n(B) is no of people reading news paper B.
if 63 % people read news A and 76% people read news B then definitely less than or equal to 100 % people read news A or news B.
i.e., n(A ∪ B) ≤ 100
⇒n(A) + n(B) - n(A ∩ B) ≤ 100
⇒63 + 76 - x ≤ 100
⇒139 - x ≤ 100
⇒x ≤ 39 .....(1)
but we know, n(A ∩ B) ≤ n(A)
so, x ≤ 63 .....(2)
from equations (1) and (2) we get,
39 ≤ x ≤ 63
now see only option (4) 55, is correct choice.
Therefore the value of x may be 55 %
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