JEE MAINS MATHS QUESTION SEPTEMBER 2020
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For a complex z=a+bi, the following four numbers are
- a+bi
- a-bi (against x axis)
- -a-bi (against origin)
- -a+bi (against y axis)
Think outside the box
But it can be taken as parallel movements of a vertice (x, y).
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Now, these four vertices definitely form a square if x=y. So, let us take one length, take (x, y) and (x, -y).
We get y=2, so we have x=y=2.
|z| can be taken as length of (2, 2) from the origin. So, |z| becomes 2√2.
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