Question

JEE MAINS PHYSICS QUESTION SEPTEMBER 2020

Answer 1

Answer:

1 will be the answer because emission doesn't depend upon intensity of light.

Answer 2

A light is incident on a metallic surface. Graph between stopping potential Vs and 1/λ is shown in figure.

when the intensity of light is increased at given frequency then.....

solution : from photoelectric effect,

K_max = incident energy - work function

⇒eVs = hf - Φ

now Vs = hf/e - Φ/e

here it is clear that frequency of light remains constant so, graph between stopping potential and (1/λ) doesn't change when intensity of light is increased.

Therefore the correct option is (1) Graph doesn't change.