JEE MAINS PHYSICS QUESTION SEPTEMBER 2020
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A rocker moving in free space has varying mass due to fuel exhausted as dm(t)/dt = -bv²(t)
where m(t) = instantaneous mass
b = constant
v(t) = instantaneous velocity.
To find : if gases are ejected with velocity u, with respect to rocket, instantaneous acceleration of rocket should be.....
solution : according to Newton's second law,
F = ma
= m × du/dt
= dm/dt × u
= u(dm/dt)
so force in term of rate of change of mass is given by, F = ma = u(dm/dt)
here dM(t))dt = -bv²(t)
so, F = u × -bv²(t) = -ubv²(t)
⇒ma = -ubv²(t)
⇒a = -ubv²(t)/m(t)
Therefore the correct option is (1) ubv²(t)/m(t)
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