Question

JEE MAINS PHYSICS QUESTION SEPTEMBER 2020

Answer 1

ANSWER.

charge flow through C2 circuit is = 590

EXPLANATION.

$\sf \to \: total \: = 750 \mu \: \\ \\ \sf \to \: c_{3} = 8 \mu \: f \\ \\ \sf \to \: v_{2} = 20v \\ \\ \sf \to \: c_{1} = 15 \mu \: f$

$\sf \to \: as \: we \: know \: tha \\ \\ \sf \to \: Q \: = cv \\ \\ \sf \to \: Q \: = 8 \times 20 = 160 \mu \: f.....(1) \\ \\ \sf \to \: Q = Q_{1} + Q_{2} \\ \\ \sf \to \: 750 = 160 + Q_{2} \\ \\ \sf \to \: Q_{2} = 590$

Answer 2

$\huge\mathtt\red{Given,}$

Total 750μL charge flows through circuit

$\huge\mathtt\red{To\:find}$

Then charge flow through $C_2$ capacitance will be_?

$\huge\mathtt\red{Answer}$

$→total - 750μ \\ → c_{3} = 8μf \\ → v_{2} - 20v \\ → c_{1} = 15μf$

As we know that,

$→q = cv$

$q = 8 \times 20 = 160μf..................(i)$

$→q = q_{1}+ q_{2} \\ →750 = 160 + q_{2}$

$→ q_{2} = 590$

Hence the answer is 590.