Jee mains previous year question .
From kinematics✔️
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From a tower of height H , a particle is thrown vertically upwards with a speed u . the time taken by the particle to hit the ground is n times that taken by it to reach the highest point of it's path . the relation between H , u and n is ?
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Time taken to reach the maximum height
t₁ = u/g
if t2 is time taken to hit ground .
i.e. -H = ut₂-1/2gt₂²
But , t₂ = nt₁ (Given )
So, -H = u*nu/g - 1/2g(n²u²)/g²
-H = nu²/g -n²u²/2g
2gH = nu²(n-2) Answer
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