Question

jee mains related questions...plz give the correct ans...if u dont know plz dont reply just for the sake of points​

Answer 1

Step-by-step explanation:

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Answer 2

Given :-

A ball is thrown vertically upwards with velocity "v" from the top of a tower and it reaches the ground with speed "4v" and height of the tower is $\dfrac{nv²}{2g}$ .

To Find :-

The Value of "n"

Used Concepts :-

• v² - u² = 2as or v² - u² = 2gs
• g = 9.8 m/s²

Solution :-

First see the attachment for better understanding of the question ;

From the diagram it is clear that ;

Initial velocity of ball = u = v

Final Velocity of ball = m = 4v

g = 9.8 m/s²

Height of the tower = The distance traveled by ball = s = $\dfrac{nv²}{2g}$

By Newton's Law of motion ;

=> m² - u² = 2gs

=> ( 4v )² - ( v )² = 2 × $\dfrac{nv²}{2g} × g$

=> 16v² - v² = nv²

=> 15v² = nv²

=> n = $\dfrac{15v²}{v²}$

=> n = 15

Henceforth , Value of n is 15 .