Question

JEE Problem

For Maths Genius ☺☺⤴⤴⤴⤴​

Answer 1

$\underline{\underline{\huge\mathfrak{your\:answer}}}$

step-by-step explanation:

Given,

Eqn of circle

x^2 + y^2 = 4

Now, the pt (a,0) lies on diametric end

means it will satusfy the eqn of cirlce

=> a^2 + 0^2 = 4

=> a^2 = 4 ....................(i)

Now,

another eqn given,

x^2 - 4x - a^2 = 0

putting the value of a^2 from eqn (i)

we get,

=> x^2 -4x - 4 = 0

now, finding the determinant

D = b^2 - 4ac

Here,

a = 1

b = -4

c = -4

=> D = 1^2 - 4(-4)(-4)

=> D = 1-64

=> D = -63

Here, D is neagative

So, the roots will be imaginary and distinct.