Question

JEE question....Plz solve this question.... please its urgent

Answer 1

Answer:

Let original length be x .

In first case ∆x = 10 - x , F = 4g

In second case ∆x = 13 - x , F = (4+6)g = 10g

In Both cases Wire is same so young modulus will be same as well

$Y = \frac{Fx}{A \Delta x} \\ \\ \implies \frac{4gx}{A(10 + x)} = \frac{10gx}{A(13 + x)} \\ \\ \implies2(13 + x) = 5(10 + x) \\ \\ \implies26 + 2x = 50 + 5x \\ \\ \implies3x = 50 - 26 = 24 \\ \\ \implies x = 8 \: m$