Question

Jee revision Question

Answer 1

${\bf{direct \: answer\::}}$

☆ 9x2 + 8y2 – 8y = 16 ☆

${\bf{explanation\::}}$

☆ AO + AP + OP = 4 ☆

$☆ \: 1 + \sqrt{ {x}^{2} + ( \: y - 1} + \sqrt{ {x}^{2} + {y}^{2} } = 4 \: ☆$

$☆ \: ( \sqrt{ {x}^{2}+ {y}^{2} } \: )^{2} \: = \: ( \: 3 \: - \sqrt{ {x}^{2} + \: ( \: y - 1)^{2} = 4 } \: ☆$

$☆ \: x² + y = 9 + x² + y² - 2y + \: 1 - 6 \sqrt{ {x}^{2} + (y - 1)^{2} } \: ☆$

$☆ \: 3 \sqrt{ {x}^{2} + (y - 1) } = (5 \: – \: y) \: ☆$

☆ 9(x² + (y - 1)²) = (5 - y)² ☆

☆ 9x² + 8y² – 8y = 16 ☆

☆ Means option 3 is the right answer ✅ ☆

#hopeithelps !