Question

Jeeb par ram nam dehri par____

Answer 1

Answer:

knife

I hope this is right bro

Answer 2

Given:-

A quadratic polynomial f(x) = 4x² + 8x

To Find:-

The zeroes of the polynomial and verify the relationship between the zeroes and coefficients.

Solution:-

We are given, f(x) = 4x² + 8x

$\sf\: \: \: \: \: \: \: \:: \implies4 {x}^{2} + 8x = 0$

$\sf \: \: \: \: \: \: \: \:: \implies4x(x + 2) = 0$

$\sf \implies 4x = 0 \: \: \: OR\: \: \: x + 2= 0$

$\sf \pink{\: \: \: \: \: \: \: \:: \implies x = 0 \: \: \: (or) \: \: \: x = - 2}$

$\therefore\:\underline{\textsf{ The zeros are \textbf{0 \: and \: -2 }}}.$

Now, let us verify the relationship between the zeroes and coefficients.

We know, for a quadratic polynomial f(x) = ax² + bx + c.Where:-

Sum of zeroes = $\sf \dfrac{-b}{a}$

Product of zeroes = $\sf \dfrac{c}{a}$

→ In the given quadratic equation 4x² + 8x.

a = 4

b = 8

c = 0

$\boxed{\pink{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}$

$\sf Sum \: of \: zeroes = 0 + (-2) = -2$

$\sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{-b}{a} = \dfrac{ - 8}{4} = -2$

$\boxed{\pink{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}$

$\sf Product \: of \: zeroes = 0 \times -2 = 0$

$\sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{c}{a} = \dfrac{0}{4} = 0$

Hence Verified..!!