Math, asked by RUTIKAsansaria5678, 5 hours ago

jeevan is 3 years younger than his brother sasi. if the sum of their present ages is 19 years. what are their present ages?

Answers

Answered by parivarnalla
22

Answer:

Sasi's age is 11 and Jeevan's age is 8.

Step-by-step explanation:

Let sasi age be x.

Jeevan age = x - 3

According to question :

x + (x-3) = 19

x +x - 3 =19

2x =22

x =11

Hence sasi's present age is 11 and jeevan's age is 8.

Answered by anjumanyasmin
10

Given:

Let the present age of Jeevan be x years.

the present age of Jeevan’s brother Sasi = (x + 3) years

sum of their ages = x + (x+ 3).

x + (x+ 3)=19

x+x+3=19

2x+3=19

2x=19-3

2x=16

x=8

19-8=11

Hence jeevan age is 9 and his brother age is 11

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