Math, asked by revathidonkada, 1 day ago

Jeevan is 3 years younger than his brother Sasi. Ifthe sum of their present ages is 19 years. What are their present ages?​

Answers

Answered by TheBrainliestUser
38

Given that:

  • Jeevan is 3 years younger than his brother Sasi.
  • The sum of their present ages is 19 years.

To Find:

  • What are their present ages?

Let us assume:

  • The present age of Sasi be x.
  • Present age of Jeevan = x - 3

According to the question.

Sasi's age + Jeevan's age = 19

↠ x + x - 3 = 19

↠ 2x - 3 = 19

↠ 2x = 19 + 3

↠ 2x = 22

↠ x = 22/2

↠ x = 11

Hence,

The present ages of:

  • Sasi = x = 11 years
  • Jeevan = x - 3 = 11 - 3 = 8 years
Answered by BrainlyPhenominaL
28

Given : Jeevan is 3 years younger than his brother Sasi. If the sum of their present ages is 19 years. What are their present ages?

Solution : According to the question, Jeevan is 3 yrs younger than Sasi. The sum of their ages is 19 yrs. We need to get their present ages

Let's assume Sasi's age be α

Jeevan is 3 years younger than Sasi

So, Jeevan's age be α - 3

Now, as we know the sum of their ages is 19 yrs

  • Sum of ages = α + α - 3

  • 19 = 2α - 3

  • 19 + 3 = 2α

  • 2α = 22

  • α = 11

Present Ages :

Jeevan's age = α - 3 = 11 - 3 = 8 years

Sasi's age = α = 11 years

Verification :

Using the same process through which we got α we can verify also

Sum of ages = α + α - 3

  • 19 = 11 + 11 - 3

  • 19 = 22 - 3

  • 19 = 19

HENCE, VERIFIED

Similar questions