Jeevan is 3 years younger than his brother Sasi. Ifthe sum of their present ages is 19 years. What are their present ages?
Answers
Given that:
- Jeevan is 3 years younger than his brother Sasi.
- The sum of their present ages is 19 years.
To Find:
- What are their present ages?
Let us assume:
- The present age of Sasi be x.
- Present age of Jeevan = x - 3
According to the question.
Sasi's age + Jeevan's age = 19
↠ x + x - 3 = 19
↠ 2x - 3 = 19
↠ 2x = 19 + 3
↠ 2x = 22
↠ x = 22/2
↠ x = 11
Hence,
The present ages of:
- Sasi = x = 11 years
- Jeevan = x - 3 = 11 - 3 = 8 years
Given : Jeevan is 3 years younger than his brother Sasi. If the sum of their present ages is 19 years. What are their present ages?
Solution : According to the question, Jeevan is 3 yrs younger than Sasi. The sum of their ages is 19 yrs. We need to get their present ages
Let's assume Sasi's age be α
Jeevan is 3 years younger than Sasi
So, Jeevan's age be α - 3
Now, as we know the sum of their ages is 19 yrs
- Sum of ages = α + α - 3
- 19 = 2α - 3
- 19 + 3 = 2α
- 2α = 22
- α = 11
Present Ages :
Jeevan's age = α - 3 = 11 - 3 = 8 years
Sasi's age = α = 11 years
Verification :
Using the same process through which we got α we can verify also
Sum of ages = α + α - 3
- 19 = 11 + 11 - 3
- 19 = 22 - 3
- 19 = 19
HENCE, VERIFIED