Jennifer is planning a holiday. The hotel costs $130 per night and her flight costs $600. She has a budget of $2,000 for hotel and flights. This means Jennifer can spend a maximum of $2000 only. Set up an inequality with ‘x’ representing the number of nights.
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Given:
(i) The hotel costs $130 per night.
(ii) Cost of her flight is $600.
(iii) Jennifer's total budget is $2000 for hotel and flights.
To find:
(i) The inequality with 'x' representing the number of nights she can stay.
Solution:
Total budget is $2000.
She has already spent $600 on flights.
So, money left with her = $(2000-600)
= $1400.
Now, with this money, she needs to spend the nights in a hotel, which costs $130 per night.
So, the maximum number of nights she can stay
= Money left/Cost per night
= 1400/130
= 10.76
≈ 10 [As number of nights cant be fractional]
So, she can stay at the most 10 nights if not less.
The corresponding inequality is:
x ≤ 10
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