Jenya has 12 bills in her wallet. She has a total of $82. If she has twice as many $5 bill as $1 bills, and two more $10 bills than $5 bills, how many of each does she have?
Answers
Answered by
0
Answer by Fombitz(32297) (Show Source):
You can put this solution on YOUR website!
Let X be the number of $1 bills, F be the number of $5, T the number of $10.
1.
2.
3.
4.
Substitute eqs. 3 and 4 into eq. 2,
Then from eq. 2,
Then from eq. 3,
.
.
.
Ten $1 bills, six $5 bills, and four $10 bills.
You can put this solution on YOUR website!
Let X be the number of $1 bills, F be the number of $5, T the number of $10.
1.
2.
3.
4.
Substitute eqs. 3 and 4 into eq. 2,
Then from eq. 2,
Then from eq. 3,
.
.
.
Ten $1 bills, six $5 bills, and four $10 bills.
Ghost235:
omfg thanks 4 helping meh, itz my RSM
Answered by
7
Let $5 bills be 2x,
$1 bills would be=x (as $5 bills are 2 times more)
$10 bills would be=2x+2 (as $10 bills are 2 more than $5)
so on adding all bills and multiplying its face value, we get,
5(2x)+1(x)+10(2x+2)=82
10x+x+20x+20=82
31x+20=82
31x=62
x=2
thus $1 bills are-2, $5 bills are-2(2)=4 and $10 bills are-2(2)+2=6
hope this helps!
$1 bills would be=x (as $5 bills are 2 times more)
$10 bills would be=2x+2 (as $10 bills are 2 more than $5)
so on adding all bills and multiplying its face value, we get,
5(2x)+1(x)+10(2x+2)=82
10x+x+20x+20=82
31x+20=82
31x=62
x=2
thus $1 bills are-2, $5 bills are-2(2)=4 and $10 bills are-2(2)+2=6
hope this helps!
Similar questions