Math, asked by 341053551, 11 months ago

Jeri finds a pile of money with at least $\$200$. If she puts $\$50$ of the pile in her left pocket, gives away $\frac23$ of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away $\$200$ of the original pile and kept the rest. What are the possible values of the number of dollars in the original pile of money? (Give your answer as an interval.)

Answers

Answered by amitnrw
5

Given :  Jeri finds a pile of money with at least $200 . she puts  $50  of the pile in her left pocket, gives away 2/3 of the rest of the pile,

To find :  possible values of the number of dollars in the original pile of money

Solution:

Let say Jeri finds a pile of money   =  200 + 3M  $    

puts  $50  of the pile in her left pocket

Rest = 200 + 3M - 50  = 150 + 3M $

Give away = (2/3) (150 + 3M)  = 100 + 2M  $

Money in right Pocket = 150 + 3M - (100 + 2M)

= 50 + M  $

200 + 3M - 200 = 3M  $

50 + M  > 3M

=> 2M < 50

=> M < 25

=> 3M <  75

Money 200 + 3M  

< 275

200 $ ≤ Money in piles < 275 $

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