Question

Jeri finds a pile of money with at least 200$. If she puts 50$ of the pile in her left pocket, gives away 2/3 of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away 200$ of the original pile and kept the rest. What are the possible values of the number of dollars in the original pile of money? (Give your answer as an interval.)

Answer 1

Answer:

OK.....here's what  I  get.......

Let x be  the  additional amount over the  original $200

The greater side of the  inequality  is

Original  pile  =  (200 + x)

After  she gives away  $50  she has   (150 + x)

And  she gives (2/3)  of  this away  =  (2/3) (150 + x)

So....she  must  have  (1/3)  of this left =  (1/3)(150 + x) = amt in her right pocket

The lesser  side of the inequality  is

(x + 200)  -  200   =   x

So  we  have  that

[150 + x ] / 3  >    x

150 + x  >  3x

150  >  2x

75 > x

x < 75

So...I get  that  the original  amount  could be on this interval   (200 , 275)

MARK ME AS BRANILEST PLZ