Question

Jermaine is 3 less than 5 times his daughter's age. The sum of their ages is 45 years, Find Jermaine's age

Answer 1

Answer:

Let the Daughter age be n

Jermaine age be (5n - 3)

• According to the Question :

⇒ Sum of Ages = 45 years

⇒ Jermaine + Daughter = 45

⇒ (5n - 3) + n = 45

⇒ 5n - 3 + n = 45

⇒ 6n = 45 + 3

⇒ 6n = 48

• Dividing borh by 6

⇒ n = 8 ⠀〔 Daughter Age 〕

• Age of Jermaine :

⇢ Jermaine = (5n - 3)

⇢ Jermaine = 5(8) - 3

⇢ Jermaine = 40 - 3

⇢ Jermaine = 37 years

∴ Hence, Jermaine age is 37 years.

Answer 2

Answer:

38

Step-by-step explanation:

let, Jermaine age be x and her daughter be y

A/Q,

X-3=5y

38x-5y=3--------------(1)

also x+y =45--------(2)

eq(2)-(1) we get,

x+y=45

x-5y=3

(-) (+) (-)

--------------

6y=42

y=42/6

y=7

putting the value y in eq (1) we get,

x-5y=3

x-5*7=3

x=3+35

x=38