Question

Jerome goes to buy some flower for her wife. He has Php 780, and he's looking to buy roses for Php 28 each and carnations for Php 27 each. If Jerome buys 12 roses, what is the maximum number of carnations he can buy?​

Answer 1

Jerome has = Php 780

Price of roses = Php 28

Price of carnations = Php 27

No. of roses brought = 12

Money Left with Jerome = Total - 12(amount if roses)

$= 780 - 336$

$= 444$

No. of carnations that Jerome can purchase =

Money left - Price of Carnations

$= \frac{444}{27}$

$= 16.45$

$= 16$

Jerome can buy 16 carnations maximum