Question

Jerry is building a 1/9 scale model of a racing car if the tyres on the actual car are33cm in radius what is the radius of the tyres in the model​

Answer 1

Answer:

Since it is 1/9 scale model which means the actual volume reduces by (1/9).

So V' = V/9

So (4(pi)(r')^3)/3 = (4(pi)(r)^3)/3×9

=> (r')^3 = ((r)^3)/9

=> r' = r/(cube root of 9)

=> r' = 33/(cube root of 9)

=> r' = cube root of (35937/9)

=> r' = (cube root of (3993)) cm

= 15.864 cm

PLS MARK BRAINLIEST AND FOLLOW ME FOR MORE ANSWERS.