Question

jerry went out for a walk. he covered 150m in the 1st minute. thereafter, the distance covered by him decreased by 10m every minute. find the total distance covered by jerry in 15 minutes​

Answer 1

Given : jerry went out for a walk. he covered 150m in the 1st minute. thereafter, the distance covered by him decreased by 10m every minute. find the total distance covered by jerry in 15 minutes​

To Find : the total distance covered by jerry in 15 minutes​

Solution:

Distance covered in 1st minute = 150 m

Distance covered in 2nd minute = 140 m

Distance covered in 15 th minute = 10  m

Hence Total Distance = (15/2)(150 + 10)

= 15 * 80

= 1200 m

= 1.2 km

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Answer 2

Given :- jerry went out for a walk. he covered 150m in the 1st minute. thereafter, the distance covered by him decreased by 10m every minute. find the total distance covered by jerry in 15 minutes ?

Solution :-

→ Distance covered in 1st minutes = 150m = a

→ Distance decreased in every minute = (-10) m = common difference = d

so,

→ S(n) = (n/2)[2a + (n - 1)d]

→ S(15) = (15/2)[2*150 + 14 * (-10)]

→ S(15) = (15/2) * 160

→ S(15) = 1200 m = 1.2 km

Hence, total distance covered by jerry in 15 minutes is 1.2 km .

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