jerry went out for a walk. he covered 150m in the 1st minute. thereafter, the distance covered by him decreased by 10m every minute. find the total distance covered by jerry in 15 minutes
Answers
Given : jerry went out for a walk. he covered 150m in the 1st minute. thereafter, the distance covered by him decreased by 10m every minute. find the total distance covered by jerry in 15 minutes
To Find : the total distance covered by jerry in 15 minutes
Solution:
Distance covered in 1st minute = 150 m
Distance covered in 2nd minute = 140 m
Distance covered in 15 th minute = 10 m
Hence Total Distance = (15/2)(150 + 10)
= 15 * 80
= 1200 m
= 1.2 km
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Given :- jerry went out for a walk. he covered 150m in the 1st minute. thereafter, the distance covered by him decreased by 10m every minute. find the total distance covered by jerry in 15 minutes ?
Solution :-
→ Distance covered in 1st minutes = 150m = a
→ Distance decreased in every minute = (-10) m = common difference = d
so,
→ S(n) = (n/2)[2a + (n - 1)d]
→ S(15) = (15/2)[2*150 + 14 * (-10)]
→ S(15) = (15/2) * 160
→ S(15) = 1200 m = 1.2 km
Hence, total distance covered by jerry in 15 minutes is 1.2 km .
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