Question

jet airplane travelling at a speed of 700 km/h ejects gases in opposite direction at a speed of 2000 km/h
relative to jet plane. Calculate the velocity of gases with respect to earth

Answer 1

Explanation:

Given that speed of gas with respect to jet is 2000km/hr.

let actual speed of gas be 'x'

We know, relative speed = x+ 700

so, 2000= x+700

x= 1300km/hr.

hope it helps....

Answer 2

Hope it will helps you_✌️

Question:-

A jet airplane travelling at the speed of 700 km\h ejects gases at a speed of 2000km\h the speed of the gas relative to rocket is or (speed of latter by seen by a observer in the ground.)

Explanation:

Given,

$\Large\vec{v}_{j}\:= \: 700\:Km\:h^{-1}$

$\Large\vec{v}_{cj}\:=\: -2000 \:Km\:h^{-1}h$

( Note:- here velocity of cumbustion or gas in negative direction)

To Find :-

$\vec{v}_{c}\:=\:?$

Solution:-

$\vec{v} _{cj} =\vec{v}_{c} - \vec{v}_{j} \\ - 2000 =\vec {v} _{c} - 700 \\ - 2000 + 700 = \vec{v} _{c} \\ ➜\vec{v} _{c} = - 1300$

Note:-

$\vec{v}_{cj}$ is Velocity of cumbustion with respect to jet.

$\vec{v}_{c}$ is Velocity of cumbustion respect to the ground which we are finding.

$\vec{v}_{j}$ is Velocity of jet.

Velocity of cumbustion in 1300 Km\h in opposite direction in plane.

The speed of gas is 1300km\hr or latter

Or,

The speed observe by the observer is 1300 Km\h.

Here, All statements are correct.