Math, asked by 985019, 3 months ago

JHL Puy
07.
3
Find the amount of 4,800 for 11 years at 5% per annum.​

Answers

Answered by Vamshijupelli
1

Answer:

2640 and 7440

Step-by-step explanation:

Simple interest = (p*t*r)/100

p is the principal amount

t is the time

r is the rate of interest

S.I = (4800*11*5)/100

S.I = (48*11*5)

S.I = 2640

Total amount = 2640 + 4800 = 7440


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Answered by cooljai99
0

Answer:

2640 and 7440

Step-by-step explanation:

Simple interest = (p*t*r)/100

where p is the principal amount, t is the time and r is the rate of interest

S.I = (4800*11*5)/100

S.I = (48*11*5)

S.I = 2640

Total amount = 2640 + 4800

                        = 7440

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