jhon and Peter run a race between point between x and y which appart 10 km jhon starts at 10.10 am from x at a speed of 10 km/h reaches y and return to x at the same speed peter starts at 10.55 form x at a speed of 20km/h reaches y and came back to x at the same speed what time they meet each other
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Answer:
11.40
Step-by-step explanation:
total distance 1000m
speed of jhon=50/18mps
Peter=100/18mps
distance coved by jhon in 45 min =45*50÷18=125
relative distance at 10:54 =125
time they meet =125/(100/18-50/18)
=45m
10:55+45min=
11:40
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