jhon is faster than jude. jhon and jude each walk 20km. th sum of their speed is 9km/hr and the sum of time taken is 9hrs. what is the time taken in hours
Answers
Answered by
1
Answer:
Let x be the speed of John. Then speed of Jude =9−x
Time taken by John = x20
Time taken by Jude = 9−x20
Time (John) + Time (Jude) =9 hours.
x20+9−x20=9
20(9−x)+20x=9x(9−x)
180=81x−9x2
Divide 9 on both sides, we get
x2−9x+20=0
On factoring, we get
(x−5)(x−4)=0
x=5 or 4
Time taken by John = x20
= 520 =4 hours.
PLEASE MARK ME BRAINLIEST
Answered by
0
Answer:
Let x be the speed of John. Then speed of Jude =9−x
Time taken by John =
x
20
Time taken by Jude =
9−x
20
Time(John) + Time(Jude) =9 hours.
x
20
+
9−x
20
=9
20(9−x)+20x=9x(9−x)
180=81x−9x
2
Divide 9 on both sides, we get
x
2
−9x+20=0
On factoring, we get
(x−5)(x−4)=0
Hence, the speed of Jude is 4 kmph.
Similar questions