Math, asked by ajaykumaranshu185126, 9 months ago

jhon travelled a distance by a train for one hour 20 minute at the speed of 60 km per hour, then by a bus for 54 minutes at the speed of 50 km per hour and then by a boat for one hour 36 minute at the speed of 15 km per hour. thotal diatance travelled by him was.​

Answers

Answered by NitishGummadavelly
0

Step-by-step explanation:

distance = speed * time

To convert the speed kmph into m/sec, we multiply by 5/18

To convert the time min into sec, we multiply by 60

d= 60*5/18*20*60+50*5/18*54*60+15*5/18*96*60

d=89km

Answered by aryunguptaespn
0

Answer:

TRAIN⇒    TIME=1h 36min

                   SPEED=60km

BUS⇒         TIME=54min

                   SPEED=50km

BOAT⇒     TIME=1h 20min

                   SPEED=15km

Step-by-step explanation;

now first we need to convert 1h 36min and 1h 20min to min

first: 1h 36 min

we know that 1h=60min

so (1×60)+36min

    96min

second: 1h 20 min

so we know that 1h =60min

    (1×60)+20 min

     60+20 min

      80 min

now we aslo know that s=d/t

now interchanging their position it will be d=s×t

where d  stand for distance

           t stand for  time

  and   s stand for speed

  so for train   d= s×t

                        d=60×80

                       d=4,800 m

so for bus     d=s×t

                        d=54×50

                        d=2,700 m

 so for boat     d=s×t

                        d=96×15

                         d=1,440 m

    so for total distance jhon travelled is

                       4,800+2,700+1,440

                        8,940 m

thank you,

hope,it will help you

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