Question

JI
Ifa bedy is thrown up with the velocity of 15 m/s
then maximum height attained by the body is
(g=10ms)
(a) 11.25 m
(b) 16.2 m
(c) 24.3 m
(d) 7.62 m​

Answer 1

Answer:

a) 11.25m

Explanation:

u = 0

v = 15

a = 10

$v {}^{2} - u {}^{2} = 2as$

225 - 0 = 2×10×s

225/20 = s

11.25m = s

Answer 2

Answer:

Hmax = u² / 2g

u = 15

u² = 225

g = 10 m/s²

Hmax = 225 / 20

          = 11.25 m

hope it helped:)