jika a log 128 - a log 64 + a log 1/8=2. nilai a adalah
raoatchut191:
wat is the base of log
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a(log 128 - log 64 + log 1/8) = 2
a(log 2⁷ - log 2⁶ + log 2⁻³) = 2
a( log 2⁷ - log 2⁶ - log 2³) = 2
a(log 2⁷ /(2⁶ x 2³)) = 2
a (log 2⁻²) = 2
a(-2log 2) = 2
a(-2 x 0.301) = 2
a = - 1/0.301
a = - 100/301 ANSWER
a(log 2⁷ - log 2⁶ + log 2⁻³) = 2
a( log 2⁷ - log 2⁶ - log 2³) = 2
a(log 2⁷ /(2⁶ x 2³)) = 2
a (log 2⁻²) = 2
a(-2log 2) = 2
a(-2 x 0.301) = 2
a = - 1/0.301
a = - 100/301 ANSWER
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