Jill's mother limited her video game playing to 10 hours per week. She played on only four days, a different amount of time each day. On Saturday, she played twice as much as on Wednesday. She didn't play on Monday, Tuesday and Thursday. On Friday, she played the least of the days she played. If the times were all different and there were not any partial hours, how many hours did she play on each day?
Answers
Given:
She did not play on Monday, Tuesday and Thursday
On Saturday, she played twice as much as Wednesday
On Friday, she played the least
She played a total of 10 hours
To Find:
The number of hours she played each day given that there is no partial hours.
Solution:
She did not play on Monday, Tuesday and Thursday
⇒ She played on Wednesday, Friday, Saturday and Sunday
Given that on Friday she played the least
⇒ Assumed she played an hour (smallest possible integer) on Friday
Given he played twice as much on Saturday as on Wednesday
⇒ Let the number of hours played on Wednesday be x
⇒ The number of hours played on Saturday is 2x
⇒ Sum of hours played on Wednesday and Saturday = 3x
⇒ The numbers of hours played on these 2 days must be 6
⇒ Wednesday = x = 2 hours
⇒ Saturday = 2x = 4 hours
Deduce the number of hours played on Sunday
⇒ Number of hours played = 10 - 1 - 6
⇒ Number of hours played = 3 hours
Answer: She played 2 hours on Wednesday, 1 hour on Friday, 4 hours on Saturday and 3 hours on Sunday.
Answer:
she played 2 hours on Wednesday 1 hour on Friday 4 hours on Saturday and 3 hours on sunday