Question

Jim and Pam were on a holiday in the Amazon rainforest. Pam saw a bush of beautiful flowers that she wanted to make a garland out of, but this was across the river and they would have to jump 10 rocks to get across. They both carried old, worn-out baskets and on the return trip, Pam lost two flowers from a big hole in his basket at every jump. Jim was right behind her and he too lost two flowers at every jump, but also managed to catch one of Pam's lost flowers at every alternate jump. If they got back with a total of 37 flowers between the two of them, how many flowers did they collectively pick before they crossed the river assuming that they both collected an equal amount of flowers?​

Answer 1

Answer:

Answer:

Given :-

Jim and Pam were on a holiday in the Amazon rainforest. Pam saw a bush of beautiful flowers that she wanted to make a garland out of, but this was across the river and they would have to jump 10 rocks to get across. They both carried old, worn-out baskets and on the return trip, Pam lost two flowers from a big hole in his basket at every jump. Jim was right behind her and he too lost two flowers at every jump, but also managed to catch one of Pam's lost flowers at every alternate jump. If they got back with a total of 37 flowers between the two of them,

To Find :-

Flower collected

Solution :-

This question is completely based on our mind logic.

Starting from Case - 1

• Case - 1

Ten steps they jumped

In one step they jumped on 1 stone

So,

In 10 steps = (10 × 1) = 10 stone

And

when they take 1 step to reach

So,

10 + 1 = 11 stone

Flower lost = 2 × number of stones

Flower lost = 2 × 11 + 2 × 11

Flower lost = 22 flower + 22 = 44 flower

• Case - 2

Alternate means one then one skipped then 1

Step 1 - 1

Step 2 - 0 [Since alternate]

Step 3 - 1

Step 4 - 0 [since alternate]

Step 5 - 1

Step 6 - 0 [Since alternate]

Step 7 - 1

Step 8 - 0 [Since alternate]

Step 9 - 1

Step 10 - 0 [Since alternate]

Step 11 - 1

Flower remains = 44 - 6

Flower remains = 38

Remaining flower = 37 + 38 = 75

Answer 2

Answer:

Solution :

Given Equation

$\bf \red{x^{2} - 2x + 3}$

Sum of the zeroes

Zeroes = 1 and 2

$\sf Sum = \dfrac{-(-2)}{1}$

$\sf Sum = \dfrac{2}{1}$

Sum = 2

Product of zeroes

$\alpha \beta = \dfrac{3}{1}$

$\alpha \beta = 3$

When added by 2

$\bf \alpha + 2+ \beta + 2$

$\sf \alpha + \beta + 4$

According to the question

$\alpha + \beta = 2$

$2 + \beta = 6$

$\sf \beta = 4$

In product

$\bigg(\alpha + 2\bigg) ,\bigg(\beta + 2\bigg)$

$\sf \alpha \beta + 2\alpha + 2\beta + 4$

Taking 2 as common

$\sf \alpha \beta + 2(\alpha + \beta ) + 4$

$\sf 3 + 2(2) + 4$

$\sf 3 + 4 + 4$

$11$

Equation formed :-

x² - 6x + 11