Question

Jim and Pam were on a holiday in the Amazon rainforest. Pam saw a bush of beautiful flowers that she wanted to make a garland out of, but this was across the river and they would have to jump 10 rocks to get across. They both carried old, worn-out baskets and on the return trip, Pam lost two flowers from a big hole in his basket at every jump. Jim was right behind her and he too lost two flowers at every jump, but also managed to catch one of Pam's lost flowers at every alternate jump. If they got back with a total of 37 flowers between the two of them, how many flowers did they collectively pick before they crossed the river assuming that they both collected an equal amount of flowers?​

Answer 1

Answer:

this is the right answer

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Answer 2

Given : they would have to jump 10 rocks to get across.

Pam lost two flowers from a big hole in his basket at every jump

Jim was right behind her and he too lost two flowers at every jump, but also managed to catch one of Pam's lost flowers at every alternate jump. If they got back with a total of 37 flowers between the two of them,

To Find : they collectively pick before they crossed the river

$\huge\mathfrak\red{Solution:}$

Let say they collectively collected flowers = x

Jumps required = 10

Lost flowers in 10 jumps = 2 x 2 x 10 = 40 ( Each lost two flowers in jump)

Lost Flowers collected = 10/2 = 5 ( at alternate jump )

Hence Net flowers = x - 40 + 5 = 37

=> x = 72

they collectively pick before they crossed the river = 72