Question

Jim, Dan and David share some sweets in the ratio 6:5:2. Jim gets 32 more sweets than David. How many sweets does Dan get?

Answer 1

Gɪᴠᴇɴ :-

• Jim, Dan and David share some sweets in the ratio 6:5:2.
• Jim gets 32 more sweets than David.

Tᴏ Fɪɴᴅ :-

• How many sweets does Dan get ?

Sᴏʟᴜᴛɪᴏɴ :-

Let us Assume That, Jim, Dan and David share some sweets as 6x , 5x & 2x Respectively .

As, it is given That, Jim gets 32 more sweets than David. .

So,

→ Jim sweets - David Sweets = 32

→ 6x - 2x = 32

→ 4x = 32

Dividing Both sides by 4,

→ x = 8 .

Hence,

→ Total Sweets Dan gets = 5x = 5*8 = 40 Sweets (Ans).

Therefore, Dan gets 40 sweets.

Answer 2

GIVEN:

• Jim , Dan & David share sweets in ratio 6 : 5 : 2
• Jim gets = 32 + sweets than David

TO FIND:

• Sweets that dan got

SOLUTION:

Assuming the sweets shared in ratio 6x : 5x : 2x by Jim , Dan & David

→ 2x + 32 = 6x ( °.° Given )

→ 6x - 2x = 32

→ 4x = 32

→ x = 32/4

→ x = 8

Finding :- Sweets got by Dan

♦ Sweets got by Dan = 5x

Substituting value of x

♦ Sweets got by Dan = 5(8)

Hence, sweets got by Dan = 40 sweets