Question

Jim, Dora, Ada, and Kim together placed a total of 60 cupcakes on a tray. Jim placed 0.45 of the cupcakes, Dora placed 10 of the 60 cupcakes, Ada placed 25% of the cupcakes, and Kim placed the remaining cupcakes. Who placed the most cupcakes?

Answer 1

Given :

Total cupcakes placed : 60

Cupcakes placed by Jim : 0.45

Cupcakes placed be Dora : 10

Cupcakes placed by Ada : 25%

Remaining were placed by Kim.

To find :

The person who placed the most cupcakes.

Solution :

First, we should find the total cupcakes placed by Jim, Dora and Ada.

Cupcakes placed by Jim :

$\sf \dashrightarrow 0.45 \: of \: 60$

$\sf \dashrightarrow \dfrac{45}{100} \times 60$

$\sf \dashrightarrow \dfrac{9}{20} \times 60$

$\sf \dashrightarrow \dfrac{9 \times 60}{20} = \dfrac{540}{20}$

$\sf \dashrightarrow \cancel \dfrac{540}{20} = 27$

we also know that Dora has given 10 cupcakes

Remaining cupcakes :

$\sf \dashrightarrow 60 - (27 + 10)$

$\sf \dashrightarrow 60 - 37$

$\sf \dashrightarrow 23$

Cupcakes placed by Ada :

$\sf \dashrightarrow 25\% \: of \: 23$

$\sf \dashrightarrow \dfrac{25}{100} \times 23$

$\sf \dashrightarrow \dfrac{1}{4} \times 23$

$\sf \dashrightarrow \dfrac{1 \times 23}{4} = \dfrac{23}{4}$

$\sf \dashrightarrow \cancel \dfrac{23}{4} = 5.75$

Now, we can find the cupcakes placed by Kim.

Cupcakes placed by Kim :

$\sf \dashrightarrow 23 - 5.75$

$\sf \dashrightarrow 17.25$

Hence, Jim placed the maximum number of cupcakes.