Question

Jim keeps quarters, nickels and dimes in his change jar. He has three more quarters than dimes. If there are 52 coins in the change jar, how many of each are in the jar? ​

Answer 1

The value of the dimes is $1.00 less than the value of the quarters.

Answer 2

Answer:

Let no. of dimes = x.

Then, no. of quarters = x + 3 and no. of nickels = x - 5.

Total no. of coins = x + (x + 3) + (x - 5).

This value is equal to 52.

So, x + (x + 3) + (x - 5) = 52

or x + x + 3 + x - 5 = 52

or 3x - 2 = 52

or 3x = 52 + 2 = 54

or x = 54/3 = 18

So Sal have 18 dimes

Step-by-step explanation:

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