Math, asked by Enit9020, 11 months ago

Jim’s backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide.Jim buys sod in pieces that are 1 1/3 yards long and 1 1/3 yards wide.How many pieces of sod will Jim need to buy to cover his backyard with soda n y fg

DND n;&! Duh u.

Answers

Answered by abhi178
6
length of Jim's backyard , L = 15 5/6 = 95/6 yards
width of Jim's backyard , B = 10 2/5 = 52/5 yards

so, area of rectangular backyard = L × B

= 95/6 × 52/5

= (95 × 52)/30

= 494/3 yard²

now, Jim buys sod of length 1 1/3 = 4/3 yards and width = 1 1/3 yards = 4/3 yards .

so, area of rectangular sod = length × width

= 4/3 × 4/3 = 16/9 yard²


number of sod = area of backyard/area of sod

= (494/3)/(16/9)

= 494 × 3/16

= 92.625 ≈ 93

hence, 93 pieces of sod will Jim need to buy to cover his backyard.
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