Question

Jim throws a normal dice five times. Find out the probability that he throws no 3s​

Answer 1

Given:-

Number of possible outcomes of a normal dice in 1st throw = 6

Therefore, the total number of possible outcomes after five times of throwing a normal dice = 6×5 =30

Number of favourable outcomes = 1

Therefore, the total number of favourable outcomes after five times of throwing a normal dice = 1×6 = 6

Hence,

Probability = Total no. of favourable outcomes

Total no. of possible outcomes

=6/30

=1/5

Therefore, the probability of getting a 3 after five times of throwing a normal dice is 1/5